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Nitrogen and Sulfur

Chemistry · 11th Class (Intermediate Part 1) · BISE Lahore

70 questions

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20 questions · Periodic Table and Periodic Properties × 1, Atomic Structure × 1, Chemical Bonding × 2, Stoichiometry × 1, States and Phases of Matter × 1, Chemical Energetics × 2, Reaction Kinetics × 1, Chemical Equilibrium × 1, Acid-Base Chemistry × 1, Electrochemistry × 2, Hydrocarbons × 2, Nitrogen and Sulfur × 1, Halogens × 1, Atmosphere × 1, Basic Separation Techniques × 1, Lab Safety and Practical Skills × 1

Nitrogen and Sulfur Test

10 questions · Nitrogen and Sulfur × 10

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Showing 10 of 70 questions from this chapter. The full bank is in the chapter test below.

  1. 1

    What is the electronic configuration of a nitrogen atom?

    • A.1s2 2s2 2p3 (correct answer)
    • B.1s2 2s2 2p4
    • C.1s2 2s2 2p5
    • D.1s2 2s2 2p6
    Why: Nitrogen has atomic number 7 and five valence electrons, giving 1s2 2s2 2p3. It needs three more electrons to complete its octet.
  2. 2

    Nitrogen is unreactive at room temperature mainly because:

    • A.Its molecule is nonpolar, so it cannot approach other molecules
    • B.Its triple bond has a bond enthalpy of 944 kJ/mol (correct answer)
    • C.It has the highest first ionization energy of all the elements
    • D.Its molecules are heavier than oxygen molecules in air
    Why: Breaking the nitrogen triple bond needs 944 kJ/mol, so a large amount of energy must be supplied before nitrogen can form new bonds. Lack of polarity adds to the inertness but is not the main reason.
  3. 3

    The bond enthalpy of the nitrogen triple bond is 944 kJ/mol. How much energy is required to break all the bonds in 0.25 mol of NX2\ce{N2} molecules?

    • A.118 kJ
    • B.189 kJ
    • C.236 kJ (correct answer)
    • D.944 kJ
    Why: Energy = 0.25 mol x 944 kJ/mol = 236 kJ. Taking the inverse ratio (944 / 0.25) wrongly gives 3776 kJ.
  4. 4

    In the laboratory, a small quantity of nitrogen gas is obtained by gently heating an aqueous solution of:

    • A.ammonium chloride
    • B.ammonium sulfate
    • C.sodium nitrite
    • D.ammonium nitrite (correct answer)
    Why: NHX4NOX2(aq)\ce{NH4NO2(aq)} gives NX2(g)\ce{N2(g)} + 2H2O(l). The other ammonium salts do not decompose in this way, and heating a nitrite alone gives oxides of nitrogen rather than NX2\ce{N2}.
  5. 5

    Liquid nitrogen is preferred for rapid cooling in food transport and in medicine because it:

    • A.Dissolves grease and other fats very quickly
    • B.Boils at -195.8 °C and is chemically inert (correct answer)
    • C.Freezes water without coming into contact with it
    • D.Releases nitrogen gas that displaces oxygen
    Why: Nitrogen boils at -195.8 °C, so liquid nitrogen takes up heat very rapidly, and being inert it does not react with the material being cooled.
  6. 6

    When ammonium nitrite decomposes according to NHX4NOX2(aq)→NX2(g)+2 HX2O(l)\ce{NH4NO2(aq) -> N2(g) + 2H2O(l)}, how many moles of water are produced from 3.0 mol of ammonium nitrite?

    • A.1.5 mol
    • B.3.0 mol
    • C.6.0 mol (correct answer)
    • D.12.0 mol
    Why: The equation gives 2 mol of water for every mole of NHX4NOX2\ce{NH4NO2}, so 3.0 mol x 2 = 6.0 mol. Dividing by 2 instead of multiplying gives the wrong 1.5 mol.
  7. 7

    Which equation represents the industrial manufacture of ammonia by the Haber-Bosch process?

    • A.NX2(g)+2 HX2(g)→NX2HX4(g)\ce{N2(g) + 2H2(g) -> N2H4(g)}
    • B.2 NX2(g)+3 HX2(g)→2 NHX3(g)\ce{2N2(g) + 3H2(g) -> 2NH3(g)}
    • C.NX2(g)+3 HX2O(g)→2 NHX3(g)+OX2(g)\ce{N2(g) + 3H2O(g) -> 2NH3(g) + O2(g)}
    • D.NX2(g)+3 HX2(g)⇌2 NHX3(g)\ce{N2(g) + 3H2(g) <=> 2NH3(g)} (correct answer)
    Why: Ammonia is made by the reversible combination of nitrogen and hydrogen in the ratio 1:3. The other equations are either unbalanced or not the Haber-Bosch reaction.
  8. 8

    Ammonia is described as a Bronsted-Lowry base because it:

    • A.Accepts a proton from an acid using the lone pair on nitrogen (correct answer)
    • B.Releases hydroxide ions when it dissolves in water
    • C.Donates a proton to any acid present in the solution
    • D.Accepts an electron pair from the acid molecule
    Why: A Bronsted-Lowry base is a proton acceptor, and ammonia uses the lone pair of its nitrogen atom to take up HX+\ce{H+} and form NHX4X+\ce{NH4+}. Hydroxide ions appear only as a result of this proton transfer.
  9. 9

    The base ionization constant of ammonia in water is KbK_{b} = 1.8×10−51.8 \times 10^{-5}. What does this value show about ammonia?

    • A.It is fully ionized and behaves as a strong base
    • B.The equilibrium lies to the right, so it is a strong base
    • C.The equilibrium lies far to the left, so it is a weak base (correct answer)
    • D.It is a weaker base than water itself
    Why: A small KbK_{b} shows that only a small fraction of the ammonia molecules accept protons, so the equilibrium lies far to the left and ammonia is a weak base.
  10. 10

    What is the shape of the ammonium ion, NHX4X+\ce{NH4+}?

    • A.Linear
    • B.Pyramidal
    • C.Triangular planar
    • D.Tetrahedral (correct answer)
    Why: In NHX4X+\ce{NH4+} the lone pair of nitrogen is used to form a fourth bond, so the four N−H\ce{N-H} bonds are equal in length and point towards the corners of a tetrahedron.
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